Windows Batch Script with Menu Choices

 

@ECHO OFF

:Menu

CLS

ECHO ----------------------------------------

ECHO   Application Development Environment

ECHO ----------------------------------------

ECHO 1. JDK 8.0.392 and Tomcat 9.0.37

ECHO 2. JRE 21.0.8 and Tomcat 9.0.108

ECHO 3. Exit

ECHO ----------------------------------------

SET /P CHOICE="Enter your choice (1-3): "

IF "%CHOICE%"=="1" GOTO Option1

IF "%CHOICE%"=="2" GOTO Option2

IF "%CHOICE%"=="3" GOTO :EOF

GOTO Menu

:Option1

SET DEV_HOME=C:/Users/DevApps

SET JAVA_HOME=%DEV_HOME%/zulu8.74.0.17-ca-jdk8.0.392-win_x64

SET CATALINA_HOME=%DEV_HOME%/ApacheTomcat9_CitizenPortal

@ECHO Open JDK 8.0.392 and Tomcat 9.0.37

GOTO Common

:Option2

SET DEV_HOME=C:/Users/DevApps

SET JAVA_HOME=%DEV_HOME%/zulu21.44.17-ca-jre21.0.8-win_x64

SET CATALINA_HOME=%DEV_HOME%/apache-tomcat-9.0.108

@ECHO Open JDK 21.0.8 and Tomcat 9.0.108

GOTO Common

:Common

REM SET JAVA_HOME=C:\Program Files (x86)\Java\jre1.8.0_191

SET CATALINA_BASE=%CATALINA_HOME%

SET PATH=%JAVA_HOME%/bin;%PATH%;%CATALINA_HOME%/bin;C:\Program Files\7-Zip